Solution
Step
1- Find the pressure the gas exerts in kPa.
Step
2- Convert the temperature
from Celsius to Kelvin.
Step
3- Convert the density from
g/ml to g/L
Step
4- Solve for the molar mass
Click on each step
for extra assistance
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The pressure of the gas is 749mmHg.
We must convert the pressure from mmHg to kilopascals.
760mmHg = 101.3kPa
So
(740/760) X 101.3 = 98.63kPa
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23 degrees Celsius is (273 + 23) = 296o K
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The density needs to be converted
to g/litre.
To convert millilitres into litres we divide by 1000
So!
0.0098g/ml = 9.8g/L
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Place the values of each variable in the formula and solve for the formula weight.
M = (9.8 X 8.31 X 296) / 98.63 = 244.4 atomic mass units
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The
ideal gas equation
or (2) |
Find the formula weight of an unknown gas, if its density is 0.0098g/ml at 23oC and 749mmHg pressure.
|
Back to the ideal gas equation