|
Record the results
|
(1)Weight of crucible
|
(2) Weight of crucible and magnesium ribbon
|
(3) Weight of magesium ribbon
|
|
32.34 grams
|
32.74 grams
|
0.40 grams
|
|
(4) Weight of crucible and magnesium oxide
|
(5) Mass of oxygen that reacted
|
|
33.01 grams
|
(33.01 - 32.74) = 0.27 grams
|
Calculate the mole of magnesium metal (mass/molar mass) = 0.40/24 =0.017mole
Calculate the mole of oxygen that reacted (mass/molar mass) = 0.27/16
=0.017mole
|
|
Magnesium
|
:
|
Oxygen
|
|
Moles
|
0.017
|
:
|
0.017
|
|
Ratio
|
1
|
:
|
1
|
|
Simplest ratio
|
1
|
:
|
1
|
So for every one atom of magnesium one atom of oxygen is present
Now conduct your own investigation with your own sample (approximately
0.5 grams) of magnesium.
|