0.415 g of a pure acid, H₂X(s), is added to exactly 100 mL of 0.105 M NaOH(aq).
A reaction occurs according to the equation
H₂X(s) + 2NaOH(aq) → Na₂X(aq) + 2H₂O(l)

The NaOH is in excess. This excess NaOH requires 25.21 mL of 0.197 M HCl(aq) for neutralisation. Calculate

i. the amount, in mol, of NaOH that is added to the acid H₂X initially.

Solution

ii. the amount, in mol, of NaOH that reacts with the acid H₂X

Solution.

iii. the molar mass, in g/mol, of the acid H₂X.

Solution