redox reactions - advanced exercises part 4

The animation below reveals most of the answers to the problem.

It is easier to see which species is the oxidant and which is the reductant if we place them in order of oxidant strength according to the half cell potential.

The arrow indicates that reductant (Pb) will react with an oxidant (chlorine gas) above it on the electrochemical series.
The cell potential difference = 1.36 - -0.13 = 1.49V

The anode is where oxidation takes place and in a galvanic cell this has a polarity of (-). In this case the anode is formed by the lead electrode.
The inert electrode forms the cathode(+) as this is where reduction (electron usage) occurs.

Hide solution

Advanced exercises

part 4

A galvanic cell,pictured on the right, was set up by a student in class. Irene made a salt bridge by dipping folded filter paper into a solution of potassium nitrate. She was then asked to: :

- identify the cathode and anode and give the polarity of each.
- indicate the direction of electron flow
- state the reading on the voltmeter
- write the overall reaction when the cell is discharging
- identify the oxidant and the reductant.
- indicate the charge on the ions flowing into each half cell.

Advanced exercises part 4
A galvanic cell,pictured on the right, was set up by a student in class. Irene made a salt bridge by dipping folded filter paper into a solution of potassium nitrate. She was then asked to: : - identify the cathode and anode and give the polarity of each. - indicate the direction of electron flow - state the reading on the voltmeter - write the overall reaction when the cell is discharging - identify the oxidant and the reductant. - indicate the charge on the ions flowing into each half cell. Solution