Solution
Step 1 Calculate
the mole of sodium carbonate added
with the burette
Mole = volume X concentration
= 0.02311 X 0.2 = 0.0046
Step 2 Using the equation below calculate the number of mole of hydrochloric acid present required to react completely with 0.0046 mole sodium carbonate
0.0046 X 2 = 0.0092mole of hydrochloric acid in the 25ml sample.
Step 3 Find the mole of HCl in the original sample
(250/25) X 0.0092
=0.092 mole of HCl are present in the original 25ml sample of the concrete
cleaner.
Step 4 -Find the concentration of HCl in the original concrete cleaner.
mole of HCl /volume = Molarity = 0.092 /0.025 = 3.68M
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Volumetric analysis exercise 13 |
Jonathon was asked to calculate the percentage by mass of ammonium sulfate in a brand of lawn fertiliser called "Razman's Quick Grow" . Jonathon placed 0.920 grams of lawn food in a flask. He then added 50ml of 0.3M NaOH solution and heated the solution to boiling point for ten minutes. The excess base in the solution was titrated with 0.1M sulfuric acid and an average, concordant, titre of 19.98mls was obtained. Sulfuric acid reacts with ammonium sulfate according to the equation below. Sulfuric acid reacts with sodium hydroxide according to the equation below. What is the percentage by mass of ammonium sulfate in the lawn food Atomic mass Na =23, O =16, H=1, Cl=35.5, C =12, S=32 |
Solution |