Volumetric analysis
Exercise 2
|
Volume
|
Volume
|
Volume
|
|
| Start |
1.40
mls
|
11.40
mls
|
2.40
mls
|
| Finish |
22.22
mls
|
32.22
mls
|
22.22
mls
|
| Total |
A 20 ml sample hydrochloric acid solution was titrated against a 0.05 M sodium carbonate solution. Three separate titres were obtained and the results are shown on the left .
Calculate the concentration of hydrochloric acid in the test sample.
The equation for the reaction is shown below.
Step 1 Calculate
the mole of substance delivered from the burette. In this case sodium
carbonate
Mole = Average Volume(litres)
X Concentration
Step 2 Using
the equation calculate the number of mole of substance in the test sample.
In this case HCl.
Step 3 Find the concentration of the substance in the test sample. In this case find the concentration of acid in the 25 ml sample