Stoichiometry-using the ratios-part 2
Consider the question below.
How many mole of NaCl are needed to react completely with 6 mole of Al(NO3)3?
Lets start with 6 mole of Al(NO3)3. Looking at the equation we see that Al(NO3)3 and NaCl react in the ratio 1 : 3, respectively. For every mole of Al(NO3)3 used we need 3 times as many mole of NaCl.
We therefore conclude that 18 mole of NaCl are also used.
