Volumetric analysis
exercise 6
|
Volume
|
|
| Start |
10.40
mls
|
| Finish |
22.22
mls
|
| Total |
A 0.600gram sample of impure NaOH was dissolved in 20 mls of water. The solution was then titrated against a 0.12M HCl solution.
What is the percentage composition of NaOH in the sample.
( Atomic mass of Na = 23, H = 1, O =16 )
The equation for the reaction is shown below.
Step 1 Calculate
the mole of substance delivered from the burette. In this case HCl solution
Mole = Average Volume(litres)
X Concentration
Step 2 Using the equation calculate the number of mole of NaOH in the sample.
Step 3 Find
the mass of NaOH present in the sample.
Step 4 Calculate the percent of the mass due to NaOH.