Straight line formulae. 

v
= Final velocity v
= u+ at


Exercise How long does it take for a car to cover 60m from a standing start, with a constant acceleration of 3.0m/s/s? Extra exercises of a similar nature to this one. 
Data u = 0m/s(Standing
start) 
Formula and solution d = ut + (1/2)at^{2 60 =0 + 0.5 X 3 X t2 => 60/1.5 = t2 => square root of (40) = t => t = 6.32s} 
A car can brake in an emergency with an acceleration of 9m/s/s. If the car is travelling at 27.7m/s in a straight line, what will be the distance it travels from the time the brakes are applied until it comes to rest?  u = 27.7m/s d = ? a = 9.0m/s/s v = 0m/s (it stops) 
v ^{2} = u^{2} + 2ad 0 =(27.7)^{2}
+ 2 X 9 X d 
A car is travelling at 4.0m/s due north, when the driver suddenly presses the accelerator to the floor. Ten seconds later he takes his foot off the accelerator and notices his speed is 40.0m/s. What is the acceleration of the vehicle during this period of time. 
u = 4.0m/s 
v = u+
at 40.0 = 4.0 + a X 10 36.0 = 10a 3.6m/s/s = a 
A car travels along a straight road and passes a checkpoint at a speed of 23m/s. 23 seconds later it passes a second checkpoint travelling at 32m/s. How far apart are the two checkpoints?  u = 23m/s a = ? v = 32m/s t =23s 
d = ((u
+ v)/2)t d = ((23 + 32)/2)23 d = 27.5 X 23 d = 632.5m 